------------------------------------------------------------------------ -- The Agda standard library -- -- Some theory for commutative semigroup ------------------------------------------------------------------------ {-# OPTIONS --without-K --safe #-} open import Algebra using (CommutativeSemigroup) module Algebra.Properties.CommutativeSemigroup {a ℓ} (CS : CommutativeSemigroup a ℓ) where open CommutativeSemigroup CS open import Relation.Binary.Reasoning.Setoid setoid ------------------------------------------------------------------------------ -- Re-export the contents of semigroup open import Algebra.Properties.Semigroup semigroup public ------------------------------------------------------------------------------ -- Permutation laws for _∙_ for three factors. ------------------------------------------------------------------------------ -- Partitions (1,1). -- There are five nontrivial permutations. ------------------------------------------------------------------------------ x∙yz≈y∙xz : ∀ x y z → x ∙ (y ∙ z) ≈ y ∙ (x ∙ z) x∙yz≈y∙xz x y z = begin x ∙ (y ∙ z) ≈⟨ sym (assoc x y z) ⟩ (x ∙ y) ∙ z ≈⟨ ∙-congʳ (comm x y) ⟩ (y ∙ x) ∙ z ≈⟨ assoc y x z ⟩ y ∙ (x ∙ z) ∎ x∙yz≈z∙yx : ∀ x y z → x ∙ (y ∙ z) ≈ z ∙ (y ∙ x) x∙yz≈z∙yx x y z = begin x ∙ (y ∙ z) ≈⟨ ∙-congˡ (comm y z) ⟩ x ∙ (z ∙ y) ≈⟨ x∙yz≈y∙xz x z y ⟩ z ∙ (x ∙ y) ≈⟨ ∙-congˡ (comm x y) ⟩ z ∙ (y ∙ x) ∎ x∙yz≈x∙zy : ∀ x y z → x ∙ (y ∙ z) ≈ x ∙ (z ∙ y) x∙yz≈x∙zy _ y z = ∙-congˡ (comm y z) x∙yz≈y∙zx : ∀ x y z → x ∙ (y ∙ z) ≈ y ∙ (z ∙ x) x∙yz≈y∙zx x y z = begin x ∙ (y ∙ z) ≈⟨ comm x _ ⟩ (y ∙ z) ∙ x ≈⟨ assoc y z x ⟩ y ∙ (z ∙ x) ∎ x∙yz≈z∙xy : ∀ x y z → x ∙ (y ∙ z) ≈ z ∙ (x ∙ y) x∙yz≈z∙xy x y z = begin x ∙ (y ∙ z) ≈⟨ sym (assoc x y z) ⟩ (x ∙ y) ∙ z ≈⟨ comm _ z ⟩ z ∙ (x ∙ y) ∎ ------------------------------------------------------------------------------ -- Partitions (1,2). -- These permutation laws are proved by composing the proofs for -- partitions (1,1) with \p → trans p (sym (assoc _ _ _)). ------------------------------------------------------------------------------ x∙yz≈yx∙z : ∀ x y z → x ∙ (y ∙ z) ≈ (y ∙ x) ∙ z x∙yz≈yx∙z x y z = trans (x∙yz≈y∙xz x y z) (sym (assoc y x z)) x∙yz≈zy∙x : ∀ x y z → x ∙ (y ∙ z) ≈ (z ∙ y) ∙ x x∙yz≈zy∙x x y z = trans (x∙yz≈z∙yx x y z) (sym (assoc z y x)) x∙yz≈xz∙y : ∀ x y z → x ∙ (y ∙ z) ≈ (x ∙ z) ∙ y x∙yz≈xz∙y x y z = trans (x∙yz≈x∙zy x y z) (sym (assoc x z y)) x∙yz≈yz∙x : ∀ x y z → x ∙ (y ∙ z) ≈ (y ∙ z) ∙ x x∙yz≈yz∙x x y z = trans (x∙yz≈y∙zx _ _ _) (sym (assoc y z x)) x∙yz≈zx∙y : ∀ x y z → x ∙ (y ∙ z) ≈ (z ∙ x) ∙ y x∙yz≈zx∙y x y z = trans (x∙yz≈z∙xy x y z) (sym (assoc z x y)) ------------------------------------------------------------------------------ -- Partitions (2,1). -- Their laws are proved by composing proofs for partitions (1,1) with -- trans (assoc x y z). ------------------------------------------------------------------------------ xy∙z≈y∙xz : ∀ x y z → (x ∙ y) ∙ z ≈ y ∙ (x ∙ z) xy∙z≈y∙xz x y z = trans (assoc x y z) (x∙yz≈y∙xz x y z) xy∙z≈z∙yx : ∀ x y z → (x ∙ y) ∙ z ≈ z ∙ (y ∙ x) xy∙z≈z∙yx x y z = trans (assoc x y z) (x∙yz≈z∙yx x y z) xy∙z≈x∙zy : ∀ x y z → (x ∙ y) ∙ z ≈ x ∙ (z ∙ y) xy∙z≈x∙zy x y z = trans (assoc x y z) (x∙yz≈x∙zy x y z) xy∙z≈y∙zx : ∀ x y z → (x ∙ y) ∙ z ≈ y ∙ (z ∙ x) xy∙z≈y∙zx x y z = trans (assoc x y z) (x∙yz≈y∙zx x y z) xy∙z≈z∙xy : ∀ x y z → (x ∙ y) ∙ z ≈ z ∙ (x ∙ y) xy∙z≈z∙xy x y z = trans (assoc x y z) (x∙yz≈z∙xy x y z) ------------------------------------------------------------------------------ -- Partitions (2,2). -- These proofs are by composing with the proofs for (2,1). ------------------------------------------------------------------------------ xy∙z≈yx∙z : ∀ x y z → (x ∙ y) ∙ z ≈ (y ∙ x) ∙ z xy∙z≈yx∙z x y z = trans (xy∙z≈y∙xz _ _ _) (sym (assoc y x z)) xy∙z≈zy∙x : ∀ x y z → (x ∙ y) ∙ z ≈ (z ∙ y) ∙ x xy∙z≈zy∙x x y z = trans (xy∙z≈z∙yx x y z) (sym (assoc z y x)) xy∙z≈xz∙y : ∀ x y z → (x ∙ y) ∙ z ≈ (x ∙ z) ∙ y xy∙z≈xz∙y x y z = trans (xy∙z≈x∙zy x y z) (sym (assoc x z y)) xy∙z≈yz∙x : ∀ x y z → (x ∙ y) ∙ z ≈ (y ∙ z) ∙ x xy∙z≈yz∙x x y z = trans (xy∙z≈y∙zx x y z) (sym (assoc y z x)) xy∙z≈zx∙y : ∀ x y z → (x ∙ y) ∙ z ≈ (z ∙ x) ∙ y xy∙z≈zx∙y x y z = trans (xy∙z≈z∙xy x y z) (sym (assoc z x y))
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